[hunchentoot-devel] standalone server lw 5.0

[Pierre THIERRY]

Scribit Jonathon McKitrick dies 07/03/2007 hora 18:15:
> I'd like to understand from a lisp standpoint why this works the way
> it does.  What is it about the function operator #' that it only grabs
> the value of the symbol when first evaluated?  Is there a 'hidden'
> closure operation?

No need for this. Each symbol has an associated reference to a function.
The symbol-function operator just returns this reference. After calling
it, changing the symbol's function to another one only makes that the
function you just got a reference to is not referenced anymore by this
symbol.

If you want a function that would change when the symbol is redefined,
use the following instead of symbol-function:

(defun tracking-symbol-function (symbol)
  (lambda (&rest args) (apply
    (symbol-function symbol) args)))

Obviously there's an overhead when calling this one.

Quickly,
Pierre
-- 
nowhere.man at levallois.eu.org
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